MCQ
If f(x) = $\frac{x+1}{(x-2)(x-5)}$, then in $[0,1], f(x)$ is
  • continuous
  • B
    discontinuous
  • C
    continuous except at x = 0
  • D
    discontinuous except at x = 0

Answer

Correct option: A.
continuous
(A)
$f (x)$ being a rational function, is continuous in $[0,1]$ except at those points where the denominator $(x-2)(x-5)=0$
i.e. when $x=2$ or $x=5$
Since $2,5 \notin[0,1]$
$\therefore f (x)$ is continuous in $[0,1]$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free