MCQ
If $f(x) = \frac{x}{{x - 1}}$, then $\frac{{f(a)}}{{f(a + 1)}} = $
  • A
    $f( - a)$
  • B
    $f\left( {\frac{1}{a}} \right)$
  • $f({a^2})$
  • D
    $f\left( {\frac{{ - a}}{{a - 1}}} \right)$

Answer

Correct option: C.
$f({a^2})$
c
(c) $\frac{{f(a)}}{{f\,(a + 1)}} = \frac{{a/(a - 1)}}{{(a + 1)/a}} $

$= \frac{{{a^2}}}{{{a^2} - 1}} = f({a^2})$.

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