MCQ
If $f(x) = \frac{x}{{x - 1}}$, then $\frac{{f(a)}}{{f(a + 1)}} = $
- A$f( - a)$
- B$f\left( {\frac{1}{a}} \right)$
- ✓$f({a^2})$
- D$f\left( {\frac{{ - a}}{{a - 1}}} \right)$
$= \frac{{{a^2}}}{{{a^2} - 1}} = f({a^2})$.
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$( S 1): \lim _{ n \rightarrow \infty} \frac{1}{ n ^2}(2+4+6+\ldots \ldots \ldots+2 n)=1$
(S2) : $\lim _{ n \rightarrow \infty} \frac{1}{ n ^{16}}\left(1^{15}+2^{15}+3^{15}+\ldots \ldots \ldots .+ n ^{15}\right)=\frac{1}{16}$