MCQ
If $f(x) = \frac{x}{{x - 1}}$, then $\frac{{f(a)}}{{f(a + 1)}} = $
- A$f( - a)$
- B$f\left( {\frac{1}{a}} \right)$
- ✓$f({a^2})$
- D$f\left( {\frac{{ - a}}{{a - 1}}} \right)$
$= \frac{{{a^2}}}{{{a^2} - 1}} = f({a^2})$.
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