MCQ
If $f(x) = \int_0^x {t\sin t\,dt\,,} $ then $f'(x) = $
- A$\cos x + x\sin x$
- ✓$x\sin x$
- C$x\cos x$
- DNone of these
Now, according to Leibnitz's rule,
$f'(x) = x\,\sin x.(1) - 0 = x\sin x$.
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$I$. $f$ is continuous on the closed interval $[a, b]$
$II.$ $f$ is bounded on the open interval $(a, b)$
$III.$ If $a$ $< a_1< b_1< b$, and $f (a_1)<0< f (b_1)$, then there is $a$ number $c$ such that $a_1 < c < b_1$ and $f (c)=0$