Question
If $f(x) = \left\{ {\begin{array}{*{20}{c}} {m{x^2} + n,} \\ {nx + m,} \\ {n{x^3} + m,} \end{array}} \right.\begin{array}{*{20}{c}} {x < 0} \\ {0 \le x \le 1} \\ {x > 1} \end{array}$ .For what integers m and n does both $\mathop {\lim }\limits_{x \to 0} f(x)$ and $\mathop {\lim }\limits_{x \to 1} f(x)$ exist?

Answer

It is given that
$\mathop {\lim }\limits_{x \to 0} f(x) and \mathop {\lim }\limits_{x \to 1} f(x) $both exist.
$\Rightarrow \;\mathop {\lim }\limits_{x \to {0^ - }} f(x) and = \mathop {\lim }\limits_{x \to {0^ +}}f(x) = \mathop {\lim }\limits_{x \to {1^ + }} f(x)$
Now $\mathop {\lim }\limits_{x \to {0^- }} f(x) = \mathop {\lim }\limits_{x \to {0 }} (mx^2+ n) = n$
$\mathop {\lim }\limits_{x \to {0^ + }} f(x) = \mathop {\lim }\limits_{x \to {0 }} (nx + m) = m$
Now$ \mathop {\lim }\limits_{x \to {0^ + }} f(x) = \mathop {\lim }\limits_{x \to {0^ + }} f(x) \Rightarrow n = m ...(i)$
For $\mathop {\lim }\limits_{x \to 0} f(x)$ to exist we need $m = n$
Also, $\mathop {\lim }\limits_{x \to {1^ - }} f(x) = \mathop {\lim }\limits_{x \to {1}} (nx + m) = n + m$
$\mathop {\lim }\limits_{x \to {1^ + }} f(x) = \mathop {\lim }\limits_{x \to {1}} (nx^3 + m) = n + m$
Now $\mathop {\lim }\limits_{x \to {1^ - }} f(x) = \mathop {\lim }\limits_{x \to {1^ + }} f(x) \Rightarrow n + m = n + m$
Thus $\mathop {\lim }\limits_{x \to 0} f(x)$ exists for any integral value of $m$ and $n.$

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