MCQ
If $f(x) = \left\{ \begin{array}{l}\frac{{{x^4} - 16}}{{x - 2}},\,\,{\rm{when}}\,\,x \ne 2\\\,\,\,\,\,\,\,\,\,\,\,\,\,16,\,{\rm{when}}\,\,x = 2\end{array} \right.$, then
- A$f(x)$ is continuous at $x = 2$
- B$f(x)$ is discountinous at $x = 2$
- C$\mathop {\lim }\limits_{x \to 2} f(x) = 16$
- DNone of these