MCQ
If $f(x) = \left\{ \begin{array}{l}1 + {x^2},\,\,\,{\rm{when\,\,}}\,0 \le x \le 1\\1 - x\,\,\,,{\rm{when\,\,}}\,\,x > 1\end{array} \right.$, then
  • A
    $\mathop {\lim }\limits_{x \to {1^ + }} f(x) \ne 0$
  • B
    $\mathop {\lim }\limits_{x \to {1^ - }} f(x) \ne 2$
  • $f(x)$ is discontinuous at $x = 1$
  • D
    None of these

Answer

Correct option: C.
$f(x)$ is discontinuous at $x = 1$
c
(c) $\mathop {\lim }\limits_{x \to 1 + } f(x) = 0$ and $\mathop {\lim }\limits_{x \to 1 - } \,\,f(x) = \,\,1 + 1 = 2$

Hence $f(x)$ is discontinuous at $x = 1$.

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