MCQ
If $f(x) = {\log _x}(\log x),$ then $f'(x)$ at $x = e$ is
- A$e$
- ✓${1 \over e}$
- C$1$
- DNone of these
==> $f'(x) = \frac{{\frac{1}{x} - \frac{1}{x}\log (\log x)}}{{{{(\log x)}^2}}} \Rightarrow f'(e) = \frac{{\frac{1}{e} - 0}}{1} = \frac{1}{e}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.