MCQ
If $f(x) = {\sin ^2}x$ and the composite function $g\{ f(x)\} = |\sin x|$, then the function $g(x)$ is equal to
- A$\sqrt {x - 1} $
- ✓$\sqrt x $
- C$\sqrt {x + 1} $
- D$ - \sqrt x $
==> $g({\sin ^2}x) = \,|\sin x|$;
$\therefore$ $g(x) = \sqrt x $.
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Then the area of the region bounded by the curves $x=0, x=\frac{1}{\sqrt{2}}$ and $y=y(x)$ in the upper half plane is :