MCQ
If $f(x) = \sin^2x$ and the composite function $\text{g(f(x))} = |\sin\text{x}|,$ then $g(x)$ is equal to:
  • A
    $\sqrt{{x}-1}$
  • $\sqrt{{x}}$
  • C
    $\sqrt{{x}+1}$
  • D
    $-\sqrt{{x}}$

Answer

Correct option: B.
$\sqrt{{x}}$
Given that $\text{f(x)}=\sin^2\text{x}$ and the composite function $\text{g(f(x))}=|\sin {x}|$
We will do it using trial and error method.
If we take $\text{g(x)}=-\sqrt{{x}}$ and $\text{f(x)}=\sin^2{x}$
$\text{g(f(x))}=\text{g}(\sin^2{x})$
$=-\sin {x}$
Which contradicts to the $\text{g(f(x))}=|\sin {x}|$
Hence, we take $\text{g(x)}=\sqrt{{x}}$
$\text{g(f(x))}=\text{g}(\sin^2 {x})$
$=\sqrt{\sin^2{x}}=|\sin {x}|$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The order and the degree of the differential equation $\left(1+3 \frac{d y}{d x}\right)^2=4 \frac{d^3 y}{d x^3}$ respectively are
If $A=\left[\begin{array}{ccc}3 & -1 & 2 \\ 2 & 1 & 3 \\ 1 & -3 & K\end{array}\right]$ is non-invertible matrix, then value of K :
$A$ and $B$ are two students. Their chances of solving a problem correctly are $\frac{1}{3}$ and $\frac{1}{4}$ respectively. If the probability of their making common error is $\frac{1}{20}$ and they obtain the same answer, then the probability of their answer to be correct is.
The restriction on n, k and p so that PY + WY will be define are:
  1. k = 3, p = n
  2. k is arbitrary, p = 2
  3. p is arbitrary, k = 3
  4. k = 2, p = 3
If $\vec{a}=\hat{i}+\hat{j}+2 \hat{k}$, then the value of $\vec{a} \cdot \vec{a}$ will be
Let $A=\left|\begin{array}{ll}1 & 0 \\ 0 & 0\end{array}\right|$, then
Integrate the following functions with respect to x: $\int\frac{\text{dx}}{4\text{x}+5}$
  1. $\frac{1}{4}\text{ In }(4\text{x}+5)+\text{c}$
  2. $\frac{1}{4}\text{ In }(4\text{x}+5)-\text{c}$
  3. $\frac{-1}{4}\text{ In }(4\text{x}+5)-\text{c}$
  4. $4\text{ In }(4\text{x}-5)-\text{c}$
If $\vec{a}=\overparen{i}-7 \overparen{j}+7 \overparen{k}$ and $\vec{b}=3 \overparen{i}-2 \overparen{j}+2 \overparen{k}$ then value of $|\vec{a} \times \vec{b}|$ is -
Find the values of $a, b, c$ and $d$ respectively if $\left[\begin{array}{cc}2 a+b & a-2 b \\ 5 c-d & 4 c+3 d\end{array}\right]=\left[\begin{array}{cc}4 & -3 \\ 11 & 24\end{array}\right]$.
Find the principal values of: $\cos ^{-1}\left(\frac{1}{2}\right)$