If f(x) = x^2 + 1, then fof(x) is equal to - Vidyadip

MCQ

If $f(x) = {x^2} + 1$, then $fof(x)$ is equal to

A
${x^2} + 1$
B
${x^2} + 2x + 2$
✓
${x^4} + 2{x^2} + 2$
D
None of these

✓

Answer

Correct option: C.

${x^4} + 2{x^2} + 2$

c
(c) $fof\,(x) = f\{ f(x)\} = {({x^2} + 1)^2} + 1 = {x^4} + 2{x^2} + 2.$

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