MCQ
If $f(x) = {x^3} - 6{x^2} + 9x + 3$ be a decreasing function, then $x $ lies in
- A$( - \infty , - 1) \cap (3,\,\infty )$
- ✓$(1,\,\,3)$
- C$(3,\,\,\infty )$
- DNone of these
For decreasing $f'(x) < 0$
==> $3{x^2} - 12x + 9 < 0$
==> ${x^2} - 4x + 3 < 0$
==> $(x - 3)\,\,(x - 1) < 0$,
$\therefore$ $x \in (1,\,3)$.
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