MCQ
If $f(x) = x(\sqrt x - \sqrt {x + 1} ),$ then
  • A
    $f(x)$ is continuous but non- differentiable at $x = 0$
  • B
    $f(x)$ is differentiable at $x = 0$
  • $f(x)$ is not differentiable at $x = 0$
  • D
    None of these

Answer

Correct option: C.
$f(x)$ is not differentiable at $x = 0$
c
(c) Since the function is defined for $x \ge 0$ $i.e.$ not defined for $x < 0$.

Hence the function neither continuous nor differentiable at $x = 0$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free