Question
If $f(x)=3 x^2-5 x+7$, find $f(x-1)$

Answer

$\begin{aligned} & f(x)=3 x^2-5 x+7 \\ & \therefore f(x-1)=3(x-1)^2-5(x-1)+7 \\ & =3\left(x^2-2 x+1\right)-5(x-1)+7 \\ & =3 x^2-6 x+3-5 x+5+7 \\ & =3 x^2-11 x+15\end{aligned}$

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