Question
If $f(x)=3\left(4^{x+1}\right)$, find $f(-3)$.

Answer

$ f(x)=3\left(4^{x+1}\right)$
$\therefore f(-3)=3\left(4^{-3+1}\right)$
$=3\left(4^{-2}\right)$
$=\frac{3}{16} $

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