MCQ
If $f(x)=\cos (\log x)$, then$f(x) f(y)-\frac{1}{2}[f(x / y)+f(x y)]=$
  • A
    -1
  • B
    $\frac{1}{2}$
  • C
    -2
  • $0$

Answer

Correct option: D.
$0$
(D)
Given, $f (x)=\cos (\log x) \Rightarrow f (y)=\cos (\log y)$
Then, $f (x) . f (y)-\frac{1}{2}\left[ f \left(\frac{x}{y}\right)+ f (x y)\right]$
$=\cos (\log x) \cos (\log y)$
$-\frac{1}{2}\left[\cos \left(\log \frac{x}{y}\right)+\cos (\log x y)\right]$
$=\cos (\log x) \cos (\log y)$
$-\frac{1}{2}[2 \cos (\log x) \cos (\log y)]=0$

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