MCQ
If $f(x)=\sin ^{-1}\left(\sqrt{\frac{1-x}{2}}\right)$, then $f^{\prime}(x)=$ ?
  • A
    $\frac{-1}{2 \sqrt{1+x^2}}$
  • $\frac{-1}{2 \sqrt{1-x^2}}$
  • C
    $\frac{1}{\sqrt{1-x^2}}$
  • D
    $\frac{1}{2 \sqrt{1+x^2}}$

Answer

Correct option: B.
$\frac{-1}{2 \sqrt{1-x^2}}$
B

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