MCQ
If $\text{HCF} \ (26, 169) = 13,$ then $\text{LCM}\ (26, 169) =$
- A$26.$
- B$52.$
- ✓$338.$
- D$13.$
✓
Answer
Correct option: C.
$338.$
$\text{HCF}\ (26, 169) = 13$
$\text{LCM}\ (26, 169) =\frac{26\times169}{13}=338$
$\text{LCM}\ (26, 169) =\frac{26\times169}{13}=338$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The vertices of a triangle $OAB$ are $O (0,0), A (4,0)$ and $B (0,6)$. The median $AD$ is drawn on $OB$ . The length $A D$ is
→The sum and product of the zeroes of the polynomial $x^2-6 x+8$ are respectively :
→If $d$ is the $\text{HCF}$ of $56$ and $72,$ the values of $x, y$ satisfying $d = 56x + 72y$ :
→If $x = -y$ and $y > 0$, which of the following is wrong?
→$\frac{2 \tan 30^{\circ}}{1+\tan ^2 30^{\circ}}$ is equal to
→If $5\tan\theta-4=0,$ then the value of $\frac{5\sin\theta-4\cos\theta}{5\sin\theta+4\cos\theta}$ is:
→The ratio of the sum and product of the roots of the quadratic equation $5 x^2-6 x+21=0$ is
→If the arithmetic mean of 7, 8, x, 11, 14 is x, then x =
How many terms are there in the $A.P.$ given below? $14,19,24,29,........ 119$
→Cards, each marked with one of the numbers 6, 7, 8, ..., 15 are placed in a box and mixed thoroughly. One card is drawn at random from the box. What is the probability of getting a card with number less than 10?