Question
If $I = 50\,kg-m^2$ , then ......... $N-m$ torque will be applied to stop it in $10\,sec$ . Its initial angular speed is $20\,rad/sec$ 

Answer

a
$\tau=I \alpha=\frac{I \Delta W}{\Delta t}=\frac{50(0-20)}{10}$

$\tau=-100 \mathrm{N}-\mathrm{m}$ means

$100 \mathrm{N}-\mathrm{m}$ in opposite to angular speed.

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