Question
If in any $\triangle\text{ABC},\angle\text{C}=105^\circ,\angle\text{B}=45^{\circ},\text{a}=2,$ then find b.

Answer

$\angle\text{C}=105^{\circ},\angle\text{B}=45^{\circ},\text{a}=2$ From here we can calculate that $\angle{\text{A}}=30^{\circ}$ $\text{a}\sin\text{B}=\text{b}\sin\text{A}$ $\Rightarrow2\sin45=\text{b}\sin30$ $\Rightarrow{2}\times\frac{1}{\sqrt{2}}=\text{b}\sin30$ $\Rightarrow2\times\frac{1}{\sqrt{2}}=\text{b}\times\frac{1}{2}$ $\Rightarrow{}\sqrt{2}=\frac{\text{b}}{2}$ $\Rightarrow\text{b}=2\sqrt{2}$

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