MCQ
If in two $\triangle\text{ABC}$ and $\text{PQR},\frac{\text{AB}}{\text{QR}} =\frac{\text{BC}}{\text{PR}}=\frac{\text{CA}}{\text{PQ}},$ then,
- ✓$\triangle{\text{PQR}}\sim\triangle\text{CAB}$
- B$\triangle{\text{PQR}}\sim\triangle\text{ABC}$
- C$\triangle{\text{CBA}}\sim\triangle\text{PQR}$
- D$\triangle{\text{BCA}}\sim\triangle\text{PQR}$
