MCQ
If $\int_{}^{} {\frac{{{e^x}(1 + \sin x)dx}}{{1 + \cos x}} = {e^x}f(x) + c} $, then $f(x) = $
- A$\sin \frac{x}{2}$
- B$\cos \frac{x}{2}$
- ✓$\tan \frac{x}{2}$
- D$\log \frac{x}{2}$
$I = \int_{}^{} {{e^x}\left[ {\frac{1}{2}{{\sec }^2}(x/2) + \tan (x/2)} \right]\,dx} = {e^x}.\tan (x/2) + c$
$\{ \,\,\,\int_{}^{} {{e^x}[f(x) + f'(x)\,]dx = {e^x}.\,f(x) + c\} } $
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