MCQ
If $\int_{}^{} {f(x)\,dx} = x{e^{ - \log |x|}} + f(x),$ then $f(x)$ is
- A$1$
- B$0$
- ✓$c{e^x}$
- D$\log x$
On differentiating both sides , we get $f(x) = 0 + f'(x)$
We know $\frac{d}{{dx}}({e^x}) = {e^x},\,\,$
$\therefore \,\,f(x) = c{e^x}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.