Question
If $\int_0^{ a }(2 x+1) d x=2$, find a

Answer

$\text { Given, } \int_0^{ a }(2 x+1) d x=2$
$\therefore\left[\frac{2 x^2}{2}+x\right]_0^{ a }=2$
$\therefore\left[x^2+x\right]_0^{ a }=2$
$\therefore\left[\left( a ^2+ a \right)-(0)\right]=2$
$\therefore a ^2+ a =2$
$\therefore a ^2+ a -2=0$
$\therefore a ^2+2 a - a -2=0$
$\therefore a ( a +2)-1( a +2)=0$
$\therefore(a+2)(a-1)=0$
$\therefore a +2=0 \text { or } a-1=0$
$\therefore a=-2$ or $a=1$

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