If $L$ and $R$ are respectively the inductance and resistance, then the dimensions of $\frac{R}{L}$ will be
A${T^2}$
B$T$
C${T^{ - 1}}$
D${T^{ - 2}}$
Medium
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C${T^{ - 1}}$
c (c) $L/R$ is a time constant so $(R/L) = {T^{ - 1}}$
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