MCQ
If ${\lambda _p}$ and ${\lambda _\alpha }$ be the de-Broglie's wavelengths associated with protons and $\alpha - $ particles of equal kinetic energies, then
- A${\lambda _p} = \frac{{{\lambda _\alpha }}}{4}$
- B${\lambda _p} = \frac{{{\lambda _\alpha }}}{2}$
- C${\lambda _p} = {\lambda _\alpha }$
- ✓${\lambda _p} = 2{\lambda _\alpha }$