MCQ
If ${\left( {10} \right)^9} + 2{\left( {11} \right)^1}{\left( {10} \right)^8} + 3{\left( {11} \right)^2}{\left( {10} \right)^7} + ..\;.\;.\;.\; + 10\left( {{{11}^9}} \right) = \;k{\left( {10} \right)^9}$ ,then $k $ is equal to 
  • $100$
  • B
    $110$
  • C
    $\frac{{121}}{{10}}\;$
  • D
    $\frac{{441}}{{100}}$

Answer

Correct option: A.
$100$
a
$k \cdot 10^{9}=10^{9}+2(11)^{1}(10)^{8}+3(11)^{2}(10)^{7}+\ldots$

$+10(11)^{9}$

$k=1+2\left(\frac{11}{10}\right)+3\left(\frac{11}{10}\right)^{2}+\ldots 10\left(\frac{11}{10}\right)^{9}$         ......$(i)$

$\left(\frac{11}{10}\right) k=1\left(\frac{11}{10}\right)+2\left(\frac{11}{10}\right)^{2}+\ldots+9\left(\frac{11}{10}\right)^{9}$

$+10\left(\frac{11}{10}\right)^{10}$         .......$(ii)$

On subtracting Eq. $(ii)$ from Eq. $(i),$ we get

$k\left(1-\frac{11}{10}\right)=1+\frac{11}{10}+\left(\frac{11}{10}\right)^{2}+\ldots+\left(\frac{11}{10}\right)^{9}$

$ - 10{\left( {\frac{{11}}{{10}}} \right)^{10}}$

$\Rightarrow k\left(\frac{10-11}{10}\right)=\frac{1\left[\left(\frac{11}{10}\right)^{10}-1\right]}{\left(\frac{11}{10}-1\right)}-10\left(\frac{11}{10}\right)^{10}$

$\Rightarrow-k=10\left[10\left(\frac{11}{10}\right)^{10}-10-10\left(\frac{11}{10}\right)^{10}\right]$

$\Rightarrow \quad k=100$

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