MCQ
If ${{\left( \frac{1+i\sqrt{3}}{1-i\sqrt{3}} \right)}^{n}}$ is an integer, then n is [UPSEAT 2002]
- A1
- B2
- ✓3
- D4
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$(S1):$ $2023^{2022}-1999^{2022}$ is divisible by $8.$
$(S2)$ : $13(13)^{ n }-11 n -13$ is divisible by $144$ for infinitely many $n \in N$.