Question
If ${\left( {{2 \over 3}} \right)^{x + 2}} = {\left( {{3 \over 2}} \right)^{2 - 2x}},$then $x =$

Answer

c
(c) ${\left( {{2 \over 3}} \right)^{x + 2}} = {\left( {{3 \over 2}} \right)^{2 - 2x}}$ ==> ${\left( {{2 \over 3}} \right)^{x + 2}} = {\left( {{2 \over 2}} \right)^{2 - 2x}}$.

Clearly $x + 2 = 2x - 2$ ==> $x = 4$

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