MCQ
If ${\left( {{2 \over 3}} \right)^{x + 2}} = {\left( {{3 \over 2}} \right)^{2 - 2x}},$then $x =$
- A$1$
- B$3$
- ✓$4$
- D$0$
Clearly $x + 2 = 2x - 2$ ==> $x = 4$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.