MCQ
If $\left( {a\,\,,\,\,\frac{1}{a}} \right)$ , $\left( {b\,\,,\,\,\frac{1}{b}} \right)$ , $ \left( {c\,\,,\,\,\frac{1}{c}} \right)$ $\&$ $\left( {d\,\,,\,\,\frac{1}{d}} \right)$ are four distinct points on a circle of radius $4$ units then, $abcd$ is equal to
  • A
    $4$
  • B
    $1/4$
  • $1$
  • D
    $16$

Answer

Correct option: C.
$1$
c
Let us assume that circle $: x^2 + y^2 = 16$

points are of form $\left( {t,\;\frac{1}{t}} \right)$

$\Rightarrow t^2 + \frac{1}{{{t^2}}} = 16$ should satisfy

$\Rightarrow t^4 - 16t^2 + 1 = 0 $

$\therefore$ product of roots $= 1 $

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