MCQ
If $\left[ {\begin{array}{*{20}{c}}{2 + x}&3&4\\1&{ - 1}&2\\x&1&{ - 5}\end{array}} \right]$is a singular matrix, then $x$ is
- A$\frac{{13}}{{25}}$
- ✓$ - \frac{{25}}{{13}}$
- C$\frac{5}{{13}}$
- D$\frac{{25}}{{13}}$
==> $(2 + x)(5 - 2) - 3( - 5 - 2x) + 4(1 + x) = 0$
==> $6 + 3x + 15 + 6x + 4 + 4x = 0$
==> $13x = - 25 \Rightarrow x = - \frac{{25}}{{13}}$.
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