If [ * 20 c 2& - 3 4&0 ] - [ * 20 c a&c &d ] = [ * 20 c 1&4 2& - … - Vidyadip

MCQ

If $\left[ {\begin{array}{*{20}{c}}2&{ - 3}\\4&0\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}a&c\\b&d\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&4\\2&{ - 5}\end{array}} \right]$, then $(a,b,c,d) = $

A
$(1,\,6,\,2,\,5)$
B
$(1, 2, 7, 5)$
✓
$(1, 2, -7, 5)$
D
$(-1, -2, 7, -5)$

✓

Answer

Correct option: C.

$(1, 2, -7, 5)$

c
(c) $\left[ {\begin{array}{*{20}{c}}2&{ - 3}\\4&0\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}a&c\\b&d\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&4\\2&{ - 5}\end{array}} \right]$

==> $\left[ {\begin{array}{*{20}{c}}a&c\\b&d\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}2&{ - 3}\\4&0\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}1&4\\2&{ - 5}\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&{ - 7}\\2&5\end{array}} \right]$

==> $(a,b,c,d) = (1,\,\,2,\,\, - 7,\,\,5)$.

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