MCQ
If $\left(\frac{1+ i \sqrt{3}}{1- i \sqrt{3}}\right)^{ n }$ is an integer, then n is
  • A
    1
  • B
    2
  • 3
  • D
    4

Answer

Correct option: C.
3
(C)
$\frac{1+i \sqrt{3}}{1-i \sqrt{3}}=\left(\frac{1+i \sqrt{3}}{1-i \sqrt{3}}\right)\left(\frac{1+i \sqrt{3}}{1+i \sqrt{3}}\right)$
$=\frac{-2+ i 2 \sqrt{3}}{4}$
$=\frac{-1+i \sqrt{3}}{2}=\omega$
$\therefore \quad\left(\frac{1+ i \sqrt{3}}{1- i \sqrt{3}}\right)^{ n }=\omega^{ n }=\omega^3=1 \Rightarrow n =3$

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