MCQ
If ${\left( {\frac{{1 + i\sqrt 3 }}{{1 - i\sqrt 3 }}} \right)^n}$ is an integer, then $n$ is
  • A
    $1$
  • B
    $2$
  • $3$
  • D
    $4$

Answer

Correct option: C.
$3$
c
(c) $\frac{{1 + i\sqrt 3 }}{{1 - i\sqrt 3 }} = \left( {\frac{{1 + i\sqrt 3 }}{{1 - i\sqrt 3 }}} \right)\,\left( {\frac{{1 + i\sqrt 3 }}{{1 + i\sqrt 3 }}} \right) = \frac{{ - 2 + i2\sqrt 3 }}{4}$
$ = \,\frac{{ - 1 + i\sqrt 3 }}{2} = \omega $
${\left( {\frac{{1 + i\sqrt 3 }}{{1 - i\sqrt 3 }}} \right)^n} = {\omega ^n} = {\omega ^3} = 1 \Rightarrow n = 3$.

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