Question
If $\left[\begin{array}{ll}1 & 3 \\ 0 & 0\end{array}\right]\left[\begin{array}{c}2 \\ -1\end{array}\right]=\left[\begin{array}{l}x \\ 0\end{array}\right]$ Find the value of $x$
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Answer
$\begin{aligned} & {\left[\begin{array}{ll}1 & 3 \\ 0 & 0\end{array}\right]\left[\begin{array}{c}2 \\ -1\end{array}\right]=\left[\begin{array}{l}x \\ 0\end{array}\right]} \end{aligned} $
$ \Rightarrow\left[\begin{array}{cc}2 & -3 \\ 0 & 0\end{array}\right]=\left[\begin{array}{l}x \\ 0\end{array}\right] $
$ \Rightarrow\left[\begin{array}{c}-1 \\ 0\end{array}\right]=\left[\begin{array}{l}x \\ 0\end{array}\right]$
Comparing the corresponding elements $x=-1$
$ \Rightarrow\left[\begin{array}{cc}2 & -3 \\ 0 & 0\end{array}\right]=\left[\begin{array}{l}x \\ 0\end{array}\right] $
$ \Rightarrow\left[\begin{array}{c}-1 \\ 0\end{array}\right]=\left[\begin{array}{l}x \\ 0\end{array}\right]$
Comparing the corresponding elements $x=-1$
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