MCQ
If $\left[\begin{array}{ll}2 & x \\ 0 & 1\end{array}\right]+3\left[\begin{array}{ll}2 & 1 \\ 4 & 0\end{array}\right]=\left[\begin{array}{cc}8 & 8 \\ 12 & 1\end{array}\right]$
The value of $x$ is:
  • A
    2
  • B
    3
  • C
    4
  • 5

Answer

Correct option: D.
5
(d) 5
Explanation:
Given,
$\begin{array}{l}\text { If }\left[\begin{array}{ll}2 & x \\ 0 & 1\end{array}\right]+3\left[\begin{array}{ll}2 & 1 \\ 4 & 0\end{array}\right]=\left[\begin{array}{cc}8 & 8 \\ 12 & 1\end{array}\right] \\ \Rightarrow\left[\begin{array}{ll}2 & x \\ 0 & 1\end{array}\right]+\left[\begin{array}{cc}6 & 3 \\ 12 & 0\end{array}\right]=\left[\begin{array}{cc}8 & 8 \\ 12 & 1\end{array}\right] \\ \Rightarrow\left[\begin{array}{cc}2+6 & x+3 \\ 0+12 & 1+0\end{array}\right]=\left[\begin{array}{cc}8 & 8 \\ 12 & 1\end{array}\right] \\ \Rightarrow\left[\begin{array}{cc}8 & x+3 \\ 12 & 1\end{array}\right]=\left[\begin{array}{cc}8 & 8 \\ 12 & 1\end{array}\right] \\ \Rightarrow x+3=8, x=8-3=5 \\ \Rightarrow x=5\end{array}$

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