Question
If $\left[\begin{array}{ll}a & 3 \\ 4 & 1\end{array}\right]+\left[\begin{array}{cc}2 & b \\ 1 & -2\end{array}\right]-\left[\begin{array}{cc}1 & 1 \\ -2 & c\end{array}\right]=\left[\begin{array}{ll}5 & 0 \\ 7 & 3\end{array}\right],$ Find the values of $a, b$ and $c$

Answer

$\begin{array}{l}{\left[\begin{array}{ll}a & 3 \\ 4 & 1\end{array}\right]+\left[\begin{array}{cc}2 & b \\ 1 & -2\end{array}\right]-\left[\begin{array}{cc}1 & 1 \\ -2 & c\end{array}\right]=\left[\begin{array}{ll}5 & 0 \\ 7 & 3\end{array}\right]} \end{array} $
$ {\left[\begin{array}{cc}a+1 & 2+b \\ 7 & -1-c\end{array}\right]=\left[\begin{array}{ll}5 & 0 \\ 7 & 3\end{array}\right]}$
Comparing the corresponding elements we get
$a + 1 = 5 = > a = 4$
$2 + b = 0 = > b = -2$
$-1 - c = 3 = > c = -4$

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