MCQ
If $\left[\begin{array}{lll}1 & 1 & 1 \\ 0 & 1 & 1 \\ 0 & 0 & 1\end{array}\right]\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{l}6 \\ 3 \\ 2\end{array}\right]$, then the value of $(2 x+y-z)$ is
  • A
    1
  • B
    2
  • C
    3
  • D
    5

Answer

$
\begin{array}{l}\text {}\left[\begin{array}{lll}
1 & 1 & 1 \\
0 & 1 & 1 \\
0 & 0 & 1
\end{array}\right]\left[\begin{array}{l}
x \\
y \\
z
\end{array}\right]=\left[\begin{array}{l}
6 \\
3 \\
2
\end{array}\right] \\
\therefore \quad x+y+z=6 .....(i)\\
\quad y+z=3........(ii) \\
\quad z=2.......(iii) \\
\Rightarrow \quad y+2=3
\end{array}
$
[Using (ii) and (iii)]
$
\begin{array}{l}
\Rightarrow \quad y=1 \\
\Rightarrow \quad x+1+2=6 \\
\Rightarrow \quad x=3
\end{array}
$
[Using (i), (iii) and (iv)]
So, $2 x+y-z=(2 \times 3)+1-2=6+1-2=5$

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