Question
If $\left[\begin{array}{ll}x+y & 2 x+z \\ x-y & 2 z+w\end{array}\right]=\left[\begin{array}{cc}4 & 7 \\ 0 & 10\end{array}\right]$, then the values of $x, y, z$ and $w$ respectively are

Answer

$(a)$ : Since, $\left[\begin{array}{ll}x+y & 2 x+z \\ x-y & 2 z+w\end{array}\right]=\left[\begin{array}{cc}4 & 7 \\ 0 & 10\end{array}\right]$
$\Rightarrow x+y=4 ...(i)$
$x-y=0 ...(ii)$
$2 x+z=7 ...(iii)$
and $2 z+w=10 ...(iv)$
On solving these equations, we get $x=2, y=2, z=3$ and $w=4$

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