MCQ
If $\left| {\begin{array}{*{20}{c}}
1&1&1\\
a&b&c\\
{{a^2}}&{{b^2}}&{{c^2}}
\end{array}} \right| = 5$ , then $\left| {\begin{array}{*{20}{c}}
{b{c^2} - {b^2}c}&{{a^2}c - a{c^2}}&{a{b^2} - b{a^2}}\\
{{b^2} - {c^2}}&{{c^2} - {a^2}}&{{a^2} - {b^2}}\\
{c - b}&{a - c}&{b - a}
\end{array}} \right|$ is equal to
1&1&1\\
a&b&c\\
{{a^2}}&{{b^2}}&{{c^2}}
\end{array}} \right| = 5$ , then $\left| {\begin{array}{*{20}{c}}
{b{c^2} - {b^2}c}&{{a^2}c - a{c^2}}&{a{b^2} - b{a^2}}\\
{{b^2} - {c^2}}&{{c^2} - {a^2}}&{{a^2} - {b^2}}\\
{c - b}&{a - c}&{b - a}
\end{array}} \right|$ is equal to
- A$5$
- B$15$
- ✓$25$
- D$35$