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STD 12 - 3 and 4 . determinant and metrices — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 3 and 4 . determinant and metrices4 Marks
MCQ
If $\left| {\,\begin{array}{*{20}{c}}a&b&0\\0&a&b\\b&0&a\end{array}\,} \right| = 0$, then
  • A
    $a $ is one of the cube roots of unity
  • B
    $b$ is one of the cube roots of unity
  • C
    $\left( {\frac{a}{b}} \right)$is one of the cube roots of unity
  • ✓
    $\left( {\frac{a}{b}} \right)$is one of the cube roots of $ -1$
✓

Answer

Correct option: D.
$\left( {\frac{a}{b}} \right)$is one of the cube roots of $ -1$
d
(d) Given, $\Delta = \left| {\,\begin{array}{*{20}{c}}a&b&0\\0&a&b\\b&0&a\end{array}\,} \right|\, = \,0.$
Expanding the given determinant, we get $a({a^2} - 0) - b(0 - {b^2}) = 0$ or ${a^3} + {b^3} = 0.$
This equation may be written as ${\left( {\frac{a}{b}} \right)^3} = - 1.$
Therefore, $\left( {\frac{a}{b}} \right)$ is one of the cube roots of $ -1$.

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