MCQ
If $\left| {\,\begin{array}{*{20}{c}}{x - 1}&3&0\\2&{x - 3}&4\\3&5&6\end{array}\,} \right| = 0$, then $x =$
- A$0$
- B$2$
- C$3$
- ✓$1$
==> $3{x^2} - 22x + 19 = 0 \Rightarrow (x - 1)(3x - 19) = 0$
==> $x = 1,\,19/3$.
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