MCQ
If $\left(x-\frac{1}{x}\right)^{2}=x^{2}+a+\frac{1}{x^{2}}$ then $a=$
- ✓-2
- B2
- C$2 x$
- D$-2 x$
✓
Answer
Correct option: A.
-2
$\left(x-\frac{1}{x}\right)^{2}=x^{2}-2+\frac{1}{x^{2}} \therefore a=-2$
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