MCQ
If $\lim _{x \rightarrow a} \frac{ a ^x-x^a}{x^x- a ^x}=-1$, then
  • $a=1$
  • B
    $a =0$
  • C
    $a = e$
  • D
    none of these

Answer

Correct option: A.
$a=1$
(A)
$\lim _{x \rightarrow a} \frac{a^x-x^a}{x^x-a^a}=-1$
Applying L-Hospital's rule on L.H.S., we get
$\lim _{x \rightarrow a} \frac{a^x \log _e a-a x^{a-1}}{x^x\left(1+\log _e x\right)}=-1$
$\Rightarrow \frac{a^a \log _e a-a \cdot a^{a-1}}{a^a\left(1+\log _e a\right)}=-1$
$\Rightarrow \frac{\log _{ e } a -1}{\log _{ e } a +1}=-1$
$\Rightarrow \log _{ e } a -1=-\log _{ e } a -1$
$\Rightarrow 2 \log _{ e } a =0 \Rightarrow a = e ^0=1$

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