Download App

Limits — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsLimits2 Marks
MCQ
If $\lim _{x \rightarrow-a} \frac{x^9+a^9}{x+a}=9$, then $a=$
  • ✓
    $\pm 1$
  • B
    $\pm 3$
  • C
    $\pm 2$
  • D
    $\pm 4$
✓

Answer

Correct option: A.
$\pm 1$
(A)
$\lim _{x \rightarrow- a } \frac{x^9+ a ^9}{x+ a }=9$
$\Rightarrow \lim _{x \rightarrow- a } \frac{x^9-(- a )^9}{x-(- a )}=9$
$\Rightarrow 9(-a)^{9-1}=9 \Rightarrow a= \pm 1$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Limits→Limits — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

Let $f(x)=\left\{\begin{array}{ll}\frac{\sin \pi x}{5 x} ; & x \neq 0 \\ k ; & x=0\end{array}\right.$.If $f(x)$ is continuous at $x=0$, then $k =$
→
Three critics review a book. For the three critics the odds in favour of the book are $2: 5,3: 4$ and $4: 3$ respectively. The probability that the majority is in favour of the book, is given by
→
The domain of the function $f (x)=\frac{\sin ^{-1}(x-3)}{\sqrt{9-x^2}}$ is
→
If $\sin 2 \theta+\sin 2 \phi=\frac{1}{2}$ and
$\cos 2 \theta+\cos 2 \phi=\frac{3}{2}$, then $\cos ^2(\theta-\phi)=$
→
$\lim _{x \rightarrow 1} \frac{1+\log x-x}{1-2 x+x^2}=$
→
$\text {If } f(x)=\left\{\begin{array}{ll}\frac{1}{2} \sin x^2, & x \neq 0 \\0, & x=0\end{array}\right. \text {, then }$
→
If the coefficients of $x^2$ and $x^3$ in the expansion of $(3+a x)^9$ are the same, then the value of a is
→
For the lines 2x + 5y = 7 and 2x - 5y = 9 which of the following statement is true?
→
If $x=\cos 10^{\circ} \cos 20^{\circ} \cos 40^{\circ}$, then the value of $x$ is
→
If the function $f:[1, \infty) \rightarrow[1, \infty)$ is defined by $f(x)=2^{x(x-1)}$, then $f^{-1}(x)$ is
→