MCQ
If lines $a ^2 x^2+ bcy ^2= a$ $( b + c ) x y$ are mutually perpendicular, then
  • A
    $c^2+a b=0$
  • B
    $b^2+c a=0$
  • $a^2+b c=0$
  • D
    $a^2+b^2+c^2=0$

Answer

Correct option: C.
$a^2+b c=0$
(C) Given equation of pair of lines is
$a ^2 x^2+ bc y^2= a ( b + c ) x y$
$\therefore \quad A = a ^2, B= bc$
Since the lines are mutually perpendicular,
$A+B=0$
$\Rightarrow a ^2+ bc =0$

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