Question
If $\log _3\left[\log _2\left(\log _3 x\right)\right]=1$, show that $x=6561$.

Answer

$ \log _3\left[\log _2\left(\log _3 x\right)\right]=1$
$\therefore \log _2\left(\log _3 x\right)=3^1$
$\therefore \log _3 x=2^3$
$\therefore \log _3 x=8$
$\therefore x=3^8$
$\therefore x=6561 $

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