Question
If $\mathrm{f}(\mathrm{x})=\left\{\begin{array}{cc}4 x-2, & x \leq-3 \\ 5, & -3<x<3 \\ x^2, & x \geq 3\end{array}\right.$, then find
$f(5)$
$f(5)$
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$\frac{n}{8 !}=\frac{3}{6 !}+\frac{1 !}{4 !}$